Question

In a Young's double-slit experiment the wavelength of light used is 489 nm (in vacuum), and the separation between the slits is 2.4 × 10-6 m. Determine the angle that locates (a) the dark fringe for which m = 0, (b) the bright fringe for which m = 1, (c) the dark fringe for which m = 1, and (d) the bright fringe for which m = 2.

Answer #1

where d is separation between the slits

For bright fringe , d sin theta= m x wave length .

(a)For m=0 i.e. first dark fringe, d sin theta=wave length /
2

sin theta= 489 x 10 ( - 9 ) / 2.40 x 10-6/2 = 106.2x 10 ( -3)

angle=6.1 degree

(b)For m=1 i.e. first bright fringe,d sin theta=wave length

angle=12.3 degree

(c)For m=1 i.e second dark fringe ,d sin theta=3wave length /
2

angle=18.6 degree

(d)For m=2 i.e.second bright fringe,d sin theta=2wave length

angle=24.8 degree

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