An artillery shell is red with an initial velocity of 328 m/s at 51.1 degrees above the
horizontal. To clear an avalanche, it explodes on a mountainside 42.1 s after firing. What
are the (a) x and (b) y coordinates of the shell where it explodes, relative to its firing
point? What are the (c) x and (d) y components of its velocity just before it hits the
mountainside? Be sure to include the correct sign on the answers.
the horizontal compontent of velocity = 328 cos (51.1) = 205.97 m/s
after 42.1 s it is at a distance of 205.97*42.1 = 8671.42 m
the vertical component of velocity = 328 sin (51.1) = 255.26 m/s
the acceleration due to gravity = 9.8 m/s downward
so the distance travelled in 42.1 s = ut+0.5at*t
= 255.26 * 42.1 -0.5*9.8*42.1*42.1
=2061.8 m
so the components of position
x co ordinate = 8671.42 m
y co ordinate = 2061.8 m
now the horizontal velocity remains same = 205.97
as there is no acceleration in the horizontal direction
the vertical component changes as there is acceleration in downward direction
final velocity = u+at = 255.26 + (-9.8)*42.1 = -157.37
so x component of velocity = 205.97 m/s
y component = -157.37 m/s
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