A spring stretches by 0.0226 m when a 3.74-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 5.53 Hz?
Gravitational acceleration = g = 9.81 m/s2
Force constant of the spring = k
Mass of the first object = m1 = 3.74 kg
Amount the spring stretches due to the first object = X1 = 0.0226 m
m1g = kX1
(3.74)(9.81) = k(0.0226)
k = 1623.425 N/m
Mass to be attached to the spring for a frequency of vibration to be 5.53 Hz = m2
Frequency of vibration = f = 5.53 Hz
m2 = 1.344 kg
Mass of the object to be attached to the spring so that its frequency of vibration is 5.53 Hz = 1.344 kg
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