Question

In a Young's double-slit experiment the wavelength of light used
is 493 nm (in vacuum), and the separation between the slits is 1.5
× 10^{-6} m. Determine the angle that locates
**(a)** the dark fringe for which *m* = 0,
**(b)** the bright fringe for which *m* = 1,
**(c)** the dark fringe for which *m* = 1, and
**(d)** the bright fringe for which *m* =
2.

Answer #1

where d is separation between the slits

For bright fringe , d sin theta= m x wave length .

(a)For m=0 i.e. first dark fringe, d sin theta=wave length /
2

sin theta= 493 x 10^-9 / (1.5 x 10-6*2)

angle=9.439degree

(b)For m=1 i.e. first bright fringe,d sin theta=wave length

angle=19.18 degree

(c)For m=1 i.e second dark fringe ,d sin theta=3wave length /
2

angle=29.53 degree

(d)For m=2 i.e.second bright fringe,d sin theta=2wave length

angle=41.09 degree

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