Question

Two narrow slits are illuminated by a laser with a wavelength of 522 nm. The interference pattern on a screen located x = 4.80 m away shows that the third-order bright fringe is located y = 9.10 cm away from the central bright fringe. Calculate the distance between the two slits.

The screen is now moved 0.9 m further away. What is the new distance between the central and the third-order bright fringe?

Answer #1

The position of the bright fringe is given by the equation

Where

n = order of fringe = 3

x_{n} = position of n=3 fringe = 9.1 cm = 0.091 m

d = distance between the two slits

D = Distance between screen and slit = 4.8 m

= wavelength = 522 nm = 522 x
10^{-9} m

So, d = (3 x 522 x 10^{-9} x 4.8
)/0.091 m = **8.26 x 10 ^{-5} m**

**Now**

New distance between the screen and slit = 4.8 + 0.9 m = 5.7 m

Hence, x_{n} = (3 x 522 x 10^{-9} x 5.7 )/(8.26
x 10^{-5} ) m = **0.108 m**

**So,**

**Distance between the slits is 8.26 x 10 ^{-5}
m** -------------------(a)

**New distance between central and third order fringe is
0.108 m** ---------------------(b)

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