Question

A) M, a solid cylinder (M=1.67 kg, R=0.127 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.730 kg mass, i.e., F = 7.161 N. Calculate the angular acceleration of the cylinder.

B) If instead of the force F an actual mass *m* = 0.730
kg is hung from the string, find the angular acceleration of the
cylinder.

C) How far does m travel downward between 0.690 s and 0.890 s after the motion begins?

D) The cylinder is changed to one with the same mass and radius,
but a different moment of inertia. Starting from rest, the mass now
moves a distance 0.337 m in a time of 0.450 s. Find
I_{cm} of the new cylinder.

Answer #1

M, a solid cylinder (M=1.47 kg, R=0.135 m) pivots on a thin,
fixed, frictionless bearing. A string wrapped around the cylinder
pulls downward with a force F which equals the weight of a 0.690 kg
mass, i.e., F = 6.769 N. Calculate the angular acceleration of the
cylinder. Tries 0/8 If instead of the force F an actual mass m =
0.690 kg is hung from the string, find the angular acceleration of
the cylinder. Tries 0/8 How far does...

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b)If instead of the force F an actual mass m = 0.710 kg
is hung from the string, find the angular acceleration of the
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c)How far does m travel downward...

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M, a solid cylinder (M=1.59 kg, R=0.111 m) pivots on a thin,
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The resulting angular acceleration of the cylinder is 5.0 rad/s2.
What's the angular velocity after 4.0 s, in radians per second?
(The moment of inertia of the cylinder is 1 half M R...

A small, solid cylinder with mass = 20 kg and radius = 0.10 m
starts from rest and rotates without friction about a fixed axis
through its center of mass. A string is wrapped around the
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