Question

A charged particle with a mass of 4.0 x 10-3kg and a charge of 65.0x10-4C is...

A charged particle with a mass of 4.0 x 10-3kg and a charge of 65.0x10-4C is travelling at 1750 km/hr. If it enters a 32,500 N/C electric field, how much of a change in voltage is necessary to bring it to a halt? What must the sign of the voltage change be?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

given

mass m = 4.0 x 10-3 kg

charge of q = 65.0 x 10-4 C

v = 1750 km/hr

= 486 m/sec

E = 32,500 N/C electric field,

change in voltage is V = ?

we have equation 1/2 m v2 = q V

0.5 x 4.0 x 10-3 x 4862 = 65 x 10-4 x V

V = 0.5 x 4.0 x 10-3 x 4862 / 65 x 10-4

V = 72675.692 volts

so the change in voltage is V = 72675.692 volts

using V = W / Q

the charge must be positive.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Particle A of charge 3.00 x 10-4C is at the origin, particle B of charge...
1. Particle A of charge 3.00 x 10-4C is at the origin, particle B of charge -6.00 x 10-4C is at (4.00m, 0), and particle Cof charge 1.00 x 10-4C is at (0,3.00m). Find the magnitude and direction of the resultant electric force acting on C.
a) A particle with a charge of -4.0 μC and a mass of 4.9 x 10-6...
a) A particle with a charge of -4.0 μC and a mass of 4.9 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 83 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA,...
An alpha particle of charge +2e and mass 6.64 × 10-27 kg is moving in the...
An alpha particle of charge +2e and mass 6.64 × 10-27 kg is moving in the +x direction at 1.79×106 m/s. It enters a region where the electric field is 1591 N/C in the -x direction. a. How far will the alpha particle travel before it comes to a stop? 2.33 * 10^-5 m Calculate the acceleration, then use the appropriate kinematic equation. b. How much time will elapse from when the alpha particle enters the electric field to when...
A negatively charged particle of mass 6.11 x 10-23 kg is accelerated from rest through an...
A negatively charged particle of mass 6.11 x 10-23 kg is accelerated from rest through an electric potential difference of 3.5 x 103 V. After this, it enters a magnetic field of strength 0.80 T and undergoes uniform circular motion with a radius of 25 cm. Find the speed and charge of the particle 2.How many excess electrons does the particle have?
A particle of charge +3.2 x 10^-19 C is released in a uniform electric field with...
A particle of charge +3.2 x 10^-19 C is released in a uniform electric field with a voltage difference of 1 MV (Mega is x 10^6). What is the velocity of the particle after traveling 20m if it started at rest and has a mass of 6.7 x 10^-27 kg? (assume 100% energy transfer) They dud not provide the region of the voltage the only info given was that it is a uniform electric field with a voltage difference of...
A negatively-charged particle of mass 0.001 kg and charge -1 nC is launched from a particle...
A negatively-charged particle of mass 0.001 kg and charge -1 nC is launched from a particle accelerator at an initial speed of 1 km/s into empty space. The particle flies in a straight line toward a very big plate that is uniformly charged. The particle starts 0.9 m from the plate, but reaches no closer than 0.1 m. What is the surface charge density of the plate in N/m2?
A charged particle is in continuous circular motion in a plane perpendicular to a magnetic field....
A charged particle is in continuous circular motion in a plane perpendicular to a magnetic field. Draw a sketch with the magnetic field pointing into the page, and the particle travelling counter-clockwise in the plane of the page. Given a radius of motion of 0.0231 m, a magnetic field strength of 0.00500 T, a mass of 8.84 x 10-26 kg on the particle, and a linear speed of 209 m/s, determine the magnitude and sign of the particle’s charge.
A positively charged ion travelling with charge equivalent to 1e and mass 3.17 x 10^−26 kg...
A positively charged ion travelling with charge equivalent to 1e and mass 3.17 x 10^−26 kg is accelerated in a vacuum between two parallel plates with a potential difference of 5.00 x 10^2 V between them. The ions move into a uniform external field wirh a strength of 0.2T a) determine the speed of the ion as it leaves the parallel plates b) determine the magnetic force (mag and dir) experienced by the ion as it enters the magnetic field...
A positively charged particle of mass 5.60 10-8 kg is traveling due east with a speed...
A positively charged particle of mass 5.60 10-8 kg is traveling due east with a speed of 70 m/s and enters a 0.43-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 3.60 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? N (b) Determine the...
A. What must the charge (sign and magnitude) of a particle of mass 1.45 g be...
A. What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C ? Use 9.81 m/s2 for the magnitude of the acceleration due to gravity. B. What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67×10−27 kg for the mass of a proton, 1.60×10−19 C...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT