Question

Starting from rest, a basketball rolls from the top to the bottom of a hill, reaching a translational speed of 7.5 m/s. Ignore frictional losses. (a) What is the height of the hill? (b) Released from rest at the same height, a can of frozen juice rolls to the bottom of the same hill. What is the translational speed of the frozen juice can when it reaches the bottom? (a) Number Units (b) Number Units

Answer #1

**Given**

** basket ball of mass m , rolling from top of
a hill to the bottom**

** as it rolls down it would have both rotational
and translational motion**

** given that at the bottom the speed of the
ball is v = 7.5 m/s**

**as there is no frictionaal loseese then the gravitiational
potential energy at top will be completely converts into kinetic
energy at bottom**

**that is mgh = 0.5 mv^2 ==> h = 0.5*v^2 = 0.5*7.5^2 =
28.125 m**

**b) if the ball was released from rest from the top of the
hill ,the can of frozen juice is also having same
velocity**

** if there is any friction oo the surface, and
the speed does not depend on mass of the body ,
and there is no much information about the radius of the ball and
can so they can be treated as point mass then both have same speed
at the bottom**

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from rest at the same height, a can of frozen juice rolls to the
bottom of the same hill. What is the translational speed of the
frozen juice can when it reaches the bottom?

Starting from rest, a basketball rolls from the top to the
bottom of a hill, reaching a translational speed of 6.5 m/s. Ignore
frictional losses. (a) What is the height of the hill? (b) Released
from rest at the same height, a can of frozen juice rolls to the
bottom of the same hill. What is the translational speed of the
frozen juice can when it reaches the bottom?

Starting from rest, a basketball rolls from the top to the bottom
of a hill, reaching a translational speed of 5.4 m/s. Ignore
frictional losses.
(a)
What is the height of the hill?
(b)
Released from rest at the same height, a can of frozen juice rolls
to the bottom of the same hill. What is the translational speed of
the frozen juice can when it reaches the bottom?

Starting from rest, a basketball rolls from the top of a hill to
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Released from rest at the same height, a can of frozen juice rolls
to the bottom of the same hill. What is the translational speed of
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bottom of a hill, reaching a translational speed of 5.3 m/s. Ignore
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Express your answer with the appropriate units.
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a
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Group of answer choices
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Group of answer choices
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