Question

When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 3949 rpm to zero in 2.75 s . What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration? (Express your answer to three significant figures.)

The answer I got was 9.71 in, but it says 'Review your calculations; you may have made a rounding error or used the wrong number of significant figures." I checked my work but I don't know where I went wrong? I already found that the angular acceleration of the blade is -150 rad/s^2 and the distance traveled by a point on the rim of the blade during the deceleration is 237 ft.

Answer 1