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A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into...

A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 16.6 cm deep. How far upward from its initial position does the mercury in the right arm rise?

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Answer #1

as both arms are open to atmosphere, pressure will be same, we can equate potential energies of liquids

the mercury in the left arm goes down a distance h while the mercury in the right arm goes up a distance h..so total distance is 2h

wghw = mg 2hm

cancel 'g' on both sides

hm = (w / 2m) * hw

hm = ( 1000 / 2 * 13600 ) * 16.6

hm = 0.61 cm

or

hm = 6.1 mm

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