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A 51.8-kg skateboarder starts out with a speed of 2.28 m/s. He does 105 J of...

A 51.8-kg skateboarder starts out with a speed of 2.28 m/s. He does 105 J of work on himself by pushing with his feet against the ground. In addition, friction does -251 J of work on him. In both cases, the forces doing the work are non-conservative. The final speed of the skateboarder is 6.36 m/s. (a) Calculate the change (PEf - PE0) in the gravitational potential energy. (b) How much has the vertical height of the skater changed? Give the absolute value.

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Answer #1

First add the work done by all the forces and equate with change in potential and kinetic energy according to work energy theorem .

This change in potential energy must equate with the mg ∆ h to find the change in height.

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