Question

A proton (q = 1.60×10−19 C , m = 1.67×10−27 kg )moves in a uniform magnetic field B⃗ =( 0.530 T )i^. At t = 0 the proton has a velocity components vx = 1.60×105 m/s , vy=0, and vz = 1.90×105 m/s .

What is the magnitude of the magnetic force acting on the proton?

What is the direction of the magnetic force acting on the proton?

In addition to the magnetic field there is a uniform electric field in the +x-direction, E⃗ =( 1.90×10⁴ V/m )i^. Will the proton have a component of acceleration in the direction of the electric field?

At t=T2, where T is the period of the circular motion of the proton, what is the x-component of the displacement of the proton from its position at t = 0?

Answer 1