A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v 4 of particle 4 at t 1 = 2.83 s given the details for the motion of particles 1, 2, and 3. particle 1: m 1 = 1.21 kg , v 1 ( t ) = ( 7.19 m / s ) + ( 0.255 m / s 2 ) × t particle 2: m 2 = 3.53 kg , v 2 ( t ) = ( 8.49 m / s ) + ( 0.399 m / s 2 ) × t particle 3: m 3 = 4.49 kg , v 3 ( t ) = ( 7.87 m / s ) + ( 0.153 m / s 2 ) × t particle 4: m 4 = 4.55 kg
Get Answers For Free
Most questions answered within 1 hours.