Question

Calculate the maximum deceleration of a car that is heading down a 9° slope (one that...

Calculate the maximum deceleration of a car that is heading down a 9° slope (one that makes an angle of 9° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the static coefficient of friction is involved--that is, the tires are not allowed to slip during the deceleration

Homework Answers

Answer #1

from the force diagram ,

Fn = mg cos9

frictional force is given as

ff = u Fn

ff = mgcos9

force equation for motion downward is given as

mg Sin9 - ff = ma                       eq-1

Torque equation is given as

ff R = Ia/R

ff = (0.5) m R2 (a/R2)

ff = (0.5) m a                       eq-2

using eq-1 and eq-2

mg Sin9 - (0.5) m a = ma

mg Sin9 = 1.5 ma

a = 2g Sin9/3

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the maximum deceleration of a car that is heading down a 11.5° slope (one that...
Calculate the maximum deceleration of a car that is heading down a 11.5° slope (one that makes an angle of 11.5° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed on all four tires and that the static coefficient of friction is involved--that is, the tires are not allowed to slip during the deceleration A) on dry concret B) on wet Concret C) on ice
calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope...
calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one ... Question: Calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one that... Calculate the maximum deceleration (in m/s2) of a car that is heading down a 8.5° slope (one that makes an angle of 8.5° with the horizontal) under the following road conditions. You may assume that the weight of the car is evenly distributed...
A car merges onto the freeway on a banked curve. The car maintains a constant velocity...
A car merges onto the freeway on a banked curve. The car maintains a constant velocity 푣 while driving on the curve, which is banked at angle theta and has a radius of curvature R. The car has mass m and the coefficient of static friction between the car’s tires and the road is meu(s). What is the maximum and minimum speed that the car can go around the banked curve without slipping? Hint: The car tends to slip up...
Calculate the acceleration of a skier heading down a 10.0 slope, assuming the coefficient of friction...
Calculate the acceleration of a skier heading down a 10.0 slope, assuming the coefficient of friction for waxed wood on wet snow (μs = 0.14, μk = 0.10). (b) Find the angle of the slope down which this skier could coast at a constant velocity. You can neglect air resistance.
A 1840-kg car travels on a banked, horizontal curve of diameter 250 m. Find the maximum...
A 1840-kg car travels on a banked, horizontal curve of diameter 250 m. Find the maximum safe speed if the coefficient of friction between the tires and the road is 0.75 and the banking angle is 5.0 degrees. Additionally, what net force does the car experience in this case?
A curve of radius 30 m is banked so that a 950-kg car traveling at 25...
A curve of radius 30 m is banked so that a 950-kg car traveling at 25 miles per hour can round it even if the road is so icy that the coefficient of static friction is approximately zero. You are commissioned to tell the local police the range of speeds at which a car can travel around this curve without skidding. Neglect the effects of air drag and rolling friction. If the coefficient of static friction between the snowy road...
1A) A car turning in a circle is acceleratring in the centripetal direction, even if the...
1A) A car turning in a circle is acceleratring in the centripetal direction, even if the speed is constant. This centripetal acceleration is the cause of a radially inward directed net force. On a level road this net force is the friction force acting from the road on the tires. You already looked at examples for this. Find an expression for the speed at which a car can negotiate the turn without any friction in the radial direction (f=0). Calculate...
You are driving your car uphill along a straight road. Suddenly, see a car cross a...
You are driving your car uphill along a straight road. Suddenly, see a car cross a red light and enter the intersection, just ahead of you. Immediately apply your brakes and skid in a straight line to stop, leaving a mark of 100 ft long by sliding. A policeman observes the whole incident, gives a ticket to the driver of the car for passing a red light. It also gives a ticket to you for exceeding the 30 mph speed...
You are driving your car uphill along a straight road. Suddenly, see a car cross a...
You are driving your car uphill along a straight road. Suddenly, see a car cross a red light and enter the intersection, just ahead of you. Immediately apply your brakes and skid in a straight line to stop, leaving a mark of 100 ft long by sliding. A policeman observes the whole incident, gives a ticket to the driver of the car for passing a red light. It also gives a ticket to you for exceeding the 30 mph speed...
1) You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction between the tires and the road to become zero. While the car is on the ice, it
1) You are making a circular turn in your car on a horizontal road when you hit a big patch of ice, causing the force of friction between the tires and the road to become zero. While the car is on the ice, itA) moves along a straight-line path away from the center of the circle.B) moves along a straight-line path toward the center of the circle.C) moves along a straight-line path in its original direction.D) continues to follow a...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT