Question

Coulomb's law for the magnitude of the force FF  QQ and  Q′Q′ dd is

|F|=K|QQ′|d2|F|=K|QQ′|d2,

where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1q1 = -17.0 nCnC , is located at x1x1 = -1.700 mm ; the second charge, q2q2 = 35.5 nCnC , is at the origin (x=0.0000)(x=0.0000).

What is the net force exerted by these two charges on a third charge q3q3 = 51.0 nCnC placed between q1q1 and q2q2 at x3x3 = -1.135 mm ?

Your answer may be positive or negative, depending on the direction of the force.

Express your answer numerically in newtons to three significant figures.

Answer 1

Use columb's law,

As one. Charge will attract the q3 and one will repel it,so net direction will be towards -be x axis.