Question

If a ping-pong ball is ejected horizontally from a bazooka at a constant velocity of 232 m/s towards a soda can sitting 1000 cm away, how much time does it take for the ball to collide with the can? = 0.0431s

The ping-pong ball from the previous problem strikes the can and continues through with a lower velocity of 112 m/s. A second soda can lie in wait some distance further down range. If the ball travels for another 0.201 seconds before colliding with second can, how far is the second can from the first can? (The motion is constant and undeflected in the vertical direction). = 2250 cm

After colliding with the previous two soda cans, the ping-pong ball continues as before with a more reduced constant velocity and collides with a wall 0.257 seconds after striking the second can. If the total distance from the end of the bazooka to the wall is 6000 cm, how fast was the ball going when it hit the wall?

A puck is moving on a low-friction table with a horizontal velocity of 70 cm/s and a vertical velocity of 27 cm/s. What is the magnitude and direction of the resultant velocity vector in polar coordinates? =75cm/s @ 69 degrees.

How long does it take for the puck in the previous problem to move 50 cm?

Answer 1

Thanks for asking.