Calculate the amount of heat, in kilojoules, required to convert 0.630 kg of mercury from a solid at -40.4 degrees C to a liquid at 130. degrees C. Round your answer to one decimal place.
The following characteristic values for mercury may be useful:
c = 130 J/kgK (assume that specific heat of mercury is the same in solid and liquid phase)
Tmp= -49 degrees C
Tbp= 457 degrees C
Lf=0.11 * 10^5 J/kg
Lv= 3.96 * 10^5 J/kg
I think question is not correctly written the melting temperature provided is not correct please check it once thank you.
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