A drill reaches 1,020 rpm in 1.23 s . What is the drill's angular acceleration in rad/s2?
given, time required , t= 1.23 sec
the angular velocity w= 1020 rpm
w= 1020/60 = 17 rps
1 revolution per sec is equal to radian per sec, hence, 17 rps corresponds to
hence, angular velocity is .
Now, angular acceleration, = angular velocity/ time
=
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