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A drill reaches 1,020 rpm in 1.23 s . What is the drill's angular acceleration in...

A drill reaches 1,020 rpm in 1.23 s . What is the drill's angular acceleration in rad/s2?

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Answer #1

given, time required , t= 1.23 sec

the angular velocity w= 1020 rpm

                             w= 1020/60 = 17 rps

1 revolution per sec is equal to radian per sec, hence, 17 rps corresponds to

hence, angular velocity is .

Now, angular acceleration, = angular velocity/ time

                                       =

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