Question

Conservation of Momentum with a Head-On Collision in a single direction/dimension/axis (Fwd/Bckwd) m1 = 1 kg...

Conservation of Momentum with a Head-On Collision in a single direction/dimension/axis (Fwd/Bckwd)

m1 = 1 kg

m2 = 2 kg

Initial:

m1 is moving with vi1 [Fwd]] towards m2 which is at rest.

Midst:

m1 collides with m2, now both are in motion.

Final:

m1 moves with new velocity vf1 in the backward direction, m2 moves with new vf2 forwards.

How does the law of conservation of momentum apply and what are the applicable formulas for the conservation of momentum (Pi1 = Pf1 + Pf2 ?)

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Total linear momentum before collision = total linear momentum after collision

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Useful Formulae potential energy:         Uspr = ½ k (Dx)2 Conservation of Momentum: p = mv; m1v1...
Useful Formulae potential energy:         Uspr = ½ k (Dx)2 Conservation of Momentum: p = mv; m1v1 + m2v2 = constant;       p(initial) = p(final); For perfectly elastic collisions ONLY:           (v1i – v2i) = - (v1f - v2f) k1 = (m1 – m2) / m1 + m2;       k2 = 2m2; v1f = k1v1i + k2v2i;       v2f = k2v1i + k1v2i; Rocket Equation Thrust = |dm/dt|*vexh;             vfinal = vinitial + vexh*ln (Minitial / Mfinal); [dm/dt] = kg/sec; 3. Perfectly Elastic Collision. Two masses...
A 1-kg particle moving with 14 m/sm/s   in the positive x-axis direction makes a head-on elastic...
A 1-kg particle moving with 14 m/sm/s   in the positive x-axis direction makes a head-on elastic collision with a stationary 3-kg particle. After collision, the two particles rebound along the x-axis. What is the final velocity of the 1-kg particle?
1) Consider an object of mass m1 = 0.425 kg moving with a uniform speed of...
1) Consider an object of mass m1 = 0.425 kg moving with a uniform speed of 6.65 m/s on a frictionless surface. This object makes an elastic head-on collision with another object of mass m2 = 0.555 kg  which is initially at rest. (a) Find the speed of m1 immediately after collision. (b) Find the speed of m2 immediately after collision. 2) An object of mass m1 = 0.395 kg  starts from rest at point  and slides down an incline surface that makes...
There is object-1 of mass m1=2.84kg moving on +x axis with the velocity of v1=9.62m/s. Object-1...
There is object-1 of mass m1=2.84kg moving on +x axis with the velocity of v1=9.62m/s. Object-1 is explode into two segments of masses m2=1.74 kg and m3=1.10kg. Mass m2 moves in +250 with the velocity of 3.57m/s. a) Find the x and y-components of velocity of mass m3 after collision? (4 points) b) Find the velocity component of x-direction of the center of mass of the two-particle system after collision. Find the velocity component of y-direction of the center of...
There is an object-1 of mass m1=1.84kg moving on +x-axis with the velocity of v1=7.62m/s. Object-1...
There is an object-1 of mass m1=1.84kg moving on +x-axis with the velocity of v1=7.62m/s. Object-1 is explode into two segments of masses m2=0.74 kg and m3=1.10kg. Mass m2 moves in +28 degrees direction on xy plane with the velocity of 1.57m/s. a) Find the x and y-components of velocity of mass m3 after collision? [Hint: you can assume the direction of m3 in any direction on xy plane with velocity components] b) Find the velocity component of x-direction of...
A bullet is fired toward a block of wood (m1 = 1.17 kg) sitting on a...
A bullet is fired toward a block of wood (m1 = 1.17 kg) sitting on a frictionless surface. The bullet has a mass mb = 30 g, and its initial velocity is 320 m/s in the +x-direction. The bullet embeds itself inside the block of wood. Then the block of wood (with bullet) collides with another block of wood (m2 = 1.20 kg). The collision is elastic. The first block moves off at an angle of -45o with respect to...
Can you solve it please Question 1: A. A m1 = 80 kg ice skater moving...
Can you solve it please Question 1: A. A m1 = 80 kg ice skater moving at 50.4 km/h due North crashes into a stationary skater of equal mass. After the collision, the two skaters move as one body at 6 m/s due North. If the collision lasts for 2.0 milliseconds, use the impulse – momentum theorem to find: i. The impulse delivered to the m1 skater due to the collision. ii. The magnitude of the average force exerted on...
EXAMPLE 6.4A Truck Versus a Compact GOAL Apply conservation of momentum to a one-dimensional inelastic collision....
EXAMPLE 6.4A Truck Versus a Compact GOAL Apply conservation of momentum to a one-dimensional inelastic collision. PROBLEM A pickup truck with mass 1.80 103 kg is traveling eastbound at +15.0 m/s, while a compact car with mass 9.00 102 kg is traveling westbound at −15.0 m/s. (See figure.) The vehicles collide head-on, becoming entangled. (a)   Find the speed of the entangled vehicles after the collision.   (b)   Find the change in the velocity of each vehicle.   (c)   Find the change in...
Questions (use complete sentences) 1) What is a conservation law? What is the basic approach taken...
Questions (use complete sentences) 1) What is a conservation law? What is the basic approach taken when using a conservation law? 2) Could the linear momentum of a turtle be greater than the linear momentum of a horse? Explain. 3) Carts A and B stick together whenever they collide. The mass of A is twice that of B. How could you roll the carts so that they would be stopped after a collision? 4) How can a satellite’s speed decrease...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT