Question

answer in J

How much energy is required to change a 36.0-g ice cube from ice at -7.0°C to steam at 114°C?

__________ J

Answer 1

Q = Q1 + Q2 + Q3 + Q4 + Q5

Q1 = energy required from -7 C ice to 0 C ice

Q2 = energy required from 0 C ice to 0 C water

Q3 = energy required from 0 C water to 100 C water

Q4 = energy required from 100 C water to 100 C steam

Q5 = energy required from 100 C steam to 114 C steam

Q1 = m*Ci*dT1

Q2 = m*Lf

Q3 = m*Cw*dT2

Q4 = m*Lv

Q5 = m*Cs*dT3

Adding all values

Q = m*(Ci*dT1 + Lf + Cw*dT2 + Lv + Cs*dT3)

m = 36 gm = 0.036 kg

Q = 0.036*(2090*7 + 3.33*10^5 + 4186*100 + 2.26*10^6 + 2010*14)

Q = 1.099*10^5 J = 1.1*10^5 J