An ac series circuit consists of a voltage source of frequency 60 Hz and voltage amplitude V, a 194-Ω resistor, and a capacitor of capacitance 8.2 μF. What must be the source voltage amplitude V for the average electrical power consumed in the resistor to be 416 W? There is no inductance in the circuit.
Express your answer using two significant figures.
we are given the power absorbed by the resistor (416 watts in a 194 Ohm Resistor)
Lets Calculate the current required using P=I^2 R,
Current = I = sqrt ( P/R) = sqrt(416/194) =1.464 Amps
we can now calculate the voltage across the resistor E=IR , E = 1.464*194 = 284.08 Volts
Xc = 1/(2*pi*f*C)
Xc = 1/ (2*3.14*60*8.2*10^-6)
Xc = 323.649 Ohms
Voltage across Capacitor, V = i*Xc = 323.649*1.464 = 473.8 V
source voltage is square root of (473.8^2+284.08^2) = 552.4 Volts~ 55*10^2 V
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