Question

A 2.15 kg mass attached to a spring oscillates with a period of 0.450 s and an amplitude of 25.0 cm.

(a) Find the total mechanical energy of the system

(b) Find the maximum speed of the mass.

Answer #1

E = 1/2*(2.15* (2π/0.45)^{2} *0.25^{2} ) =
**13.09J**

B)

At maximum speed, the kinetic energy of the object is equal to the total mechanical energy of the system. That is:

K=E

The kinetic energy of an object with mass, m, moving with velocity, v, is equal to:

K=1/2*(mv^{2} )

=> 13.09 = 0.5* 2.15 * v^{2}

V = **3.48 m/s**

**I hope it was helpful..**

****

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