Question

When light with a wavelength of 221 nm is incident on a certain
metal surface, electrons are ejected with a maximum kinetic energy
of 3.28 × 10^{−19} J. Determine the wavelength (in nm) of
light that should be used to double the maximum kinetic energy of
the electrons ejected from this surface.

Answer #1

When light with a wavelength of 258 nm is incident on a certain
metal surface, electrons are ejected with a maximum kinetic energy
of 3.02 × 10-19 J. Determine the wavelength (in nm) of
light that should be used to double the maximum kinetic energy of
the electrons ejected from this surface.

a) A photon of wavelength 43 nm is incident upon a metal in a
photoelectric apparatus. A stopping voltage of 21 V was obtained.
What is the threshold frequency of the metal? (format of a.b x
10cdHz)
b) Light with a frequency of 5.00 x 1014 Hz
illuminates a photoelectric surface that has a work function of
2.10 x 10-19 J. What is the maximum kinetic energy of
the emitted photoelectrons? (format of a.bc x 10-de J
)
c) Light...

When ultraviolet light with a wavelength of 400 nm falls on a
certain metal surface, the maximum kinetic energy of the emitted
photoelectrons is 1.10 eV .
What is the maximum kinetic energy K_0 of the photoelectrons
when light of wavelength 340 nm falls on the same surface?
Use h = 6.63×10−34 J⋅s for Planck's constant and c =
3.00×108 m/s for the speed of light and express your
answer in electron volts.
View Available Hint(s)
K_0 =
eV

When ultraviolet light with a wavelength of 400 nm falls on a
certain metal surface, the maximum kinetic energy of the emitted
photoelectrons is 1.10 eV .
What is the maximum kinetic energy K0 of the
photoelectrons when light of wavelength 330 nm falls on the same
surface?
Use h =
6.63×10?34J?s for Planck's constant and
c =
3.00×108m/s for the speed of light and
express your answer in electron volts.

1. Light of wavelength 401 nm incident on a certain metal
produces photoelectrons with a maximum kinetic energy of 1.78 eV.
What is the maximum wavelength of light capable of producing
photoelectrons for this metal?
2. Electrons in an electron microscope have been accelerated
through a potential difference of 1250 V. How large is their de
Brogile wavelength?

Light of wavelength 342 nm shines on a metal surface and the
stopping potential V0 in a photoelectric experiment is observed to
be 0.850 V.
a) What is the work function φ of the metal? (eV)
b) What is the maximum kinetic energy of the ejected electrons
(in Joules)?
c) What is the longest wavelength light that will still allow
electrons to escape the metal?(nm)

2a) When a metal surface is illuminated by light of wavelength
310 nm, the
measured maximum kinetic energy of the emitted electrons is 0.50
eV. Calculate the
metal plate’s work function φ in units of eV.
b) In the rest frame of an ejected electron from the photoelectric
experiment in part a),
an incident γ-ray with an energy of 0.25 MeV interacts with the
electron. Following
the collision, the γ-ray has a final energy of 0.1 MeV. Calculate
the angle...

When ultraviolet light with a wavelength of 400 nmfalls on a
certain metal surface, the maximum kinetic energy of the emitted
photoelectrons is 1.10 eV .
What is the maximum kinetic energy K0 of the
photoelectrons when light of wavelength 350 nm falls on the same
surface?
Use h = 6.63×10?34 J?s for Planck's constant
and c = 3.00×108 m/s for the speed of light and
express your answer in electron volts.

When a piece of metal is irradiated with UV radiation
(wavelength = 162 nm), electrons are ejected with a kinetic energy
of 3.54x10-19 J. What is the work function of the metal?
(KE=hv-phi)

A metal has a work function 2.78eV. Photons of a certain
wavelength incident on this metal produce electrons with a maximum
kinetic energy 2.33eV. Determine the wavelength of the incident
photons (in nm).

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