Question

Exercises

1. How is the image formed by the mirror different from the lenses ?

Exercises: Problem Solving

1. The focal point is found 20 cm from a double concave lens where an object is placed 12 cm. Find the image distance.??

2- A 2.8 cm diameter coin is placed 25 cm from a double concave lens with focal length of -12 cm. Find the image distance and diameter of the image??

3. An object that is 8 cm high is placed 80 cm in front of a convex (converging) lens whose focal length is 40 cm. Determine the characteristics of the image and make a summary??

4. An object that is 5 cm high is placed 25 cm in front of a convex (converging) lens whose focal length is 10 cm. Determine the characteristics of the image and summarize??.

Exercises on Problem Solving1.

(a) How long does it take the astronaut to travel 4.30 light year at 0.99944c, as measured by the earth-bound observers?(a)How long does it take according to the astronaut?

(b)Verify that the two times are related through time dilation with Ƴ = 2=30.00c as given

Exercises on Problem Solving2. (a) Find the value of Ƴ for the following situation. An astronaut measures the length of the spaceship to be 25.0 m, while an earth-bound observer measures it to be 100m

.(b) What is unreasonable about the result?

(c) Which assumptions are unreasonable or inconsistent?

Exercises1.A particle is travelling through the earth’s atmosphere at a speed of 0.750c. To and earth-bound observer, the distance it travels is 2.50km. How far does the particle travel in the particle’s reference frame?2.Suppose an astronaut travels so fast that Ƴ = 30.00(a) He travels from the earth to the nearest to the nearest star system, Alpha Centauri, 4.300 light years (ly) away as measured

Exercises2. Suppose an astronaut travels so fast that Ƴ = 30.00(a) She travels from the earth to the nearest to the nearest star system, Alpha Centauri, 4.300 light years (ly) away as measured by an earth-bound observer. How far apart are the earth and Alpha Centauri as measured by the astronaut?

Exercises2. Suppose an astronaut travels so fast that Ƴ = 30.00(b) In terms of c, what is her velocity relative to the earth (disregard motion of the earth relative to the sun)?

Exercises3. Analyze the dataLength of the spaceship as seen on board = 200 mObservation from the earth = 0.970cLength of the spaceship as measured by the earthbound observer?

Exercises4. How fast would a 6.0m-long sports car to be going fast you in order for the sports car to appear only 5.5 m long?

Exercises5. An observer on the earth, the muontravels at 0.960c for 7.05 ͷs from the time it is produced until it decays. Find the distance travelled. With a lifetime of 2.20ͷs, does the time is enough for the particle to travel?

Exercises6. (a) How fast would the athlete need to be running for a 100-m race to look 100 yard long?(b) Is the answer consistent with the fact that relativistic effects are difficult to observe in the ordinary circumstances? Explain.

Exercises7. A highway patrol officer uses a device that measures the speed of vehicles by bouncing radar off them and measuring the Doppler shift. The outgoing radar has frequency of 100 Hz and the returning echo has a frequency of 15.0Hz.What is the velocity of the vehicle? Note: 2 Doppler effect in the echoes. Be certain not to round off until the end of the problem since the effect is small.

Answer #1

Consider a convex mirror with an object placed 20 cm away and a
virtual image 15 cm into the mirror. The image appears to be 2 cm
tall
a) What is the focal length of the mirror?
b) How large is the object?
c) Adding a convex convex lens at a distance of 10 cm from the
object (halfway between the object and the mirror), with a focal
length of 6 cm, where would the final image appear?
d) Removing...

An object is placed to the left of a lens, and a real image is
formed to the right of the lens. The image is inverted relative to
the object and is one-half the size of the object. The distance
between the object and the image is 75.3 cm.
how far from the lens is the object?
what is the focal length of the lens?

An object is placed to the left of a lens, and a real
image is formed to the right of the lens. The image is inverted
relative to the object and is one-half the size of the object. The
distance between the object and the image is 117
cm. (a) How far from the lens is the
object? (b) What is the focal length of the
lens?

An object is placed to the left of a lens, and a real image is
formed to the right of the lens. The image is inverted relative to
the object and is one-half the size of the object. The distance
between the object and the image is 66 cm. (a) How far from the
lens is the object? (b) What is the focal length of the lens?

Sam is on a spaceship that travels from Earth to Proxima
Centauri at 70% the speed of light, or 0.7c, relative to Earth.
Erma is an observer on Earth. From Sam's perspective, 1.35 x
108 seconds passed between when the Earth was near him
and when Proxima Centauri is near him
First we consider velocity and time: How fast in m/s is Sam
moving as measured in the rest frame of the rocket?
How fast in m/s is Erma moving...

a real inverted image I of an object O is
formed by a certain lens (not shown); the object-image separation
is d = 31.4 cm, measured along the central axis of the
lens. The image is just half the size of the object. How far from
the object must the lens be placed? What is the focal length of
the lens?

A real image is formed by a particular lens. The
separation between the object and the image is 36 cm,
measured along the principal axis. The image is just half the size
of the object.
What kind of the lens must be used to produce this image?
How far the object is placed from the lens?
What is the focal length?
Use the graphical method to illustrate the principle of the
image formation.

The distance from earth to the center of our galaxy is about
28,000 ly (1 ly = 1 light year = 9.47 × 1015 m), as measured by an
earth-based observer. A spaceship is to make this journey at a
speed of 0.9990c. According to a clock on board the spaceship, how
long will it take to make the trip? Express your answer in years.
(1 yr is equal to 3.16 × 107 s.)

The distance from earth to the center of our galaxy is about
30,000 ly (1 ly = 1 light year = 9.47 × 1015 m), as measured by an
earth-based observer. A spaceship is to make this journey at a
speed of 0.9990c. According to a clock on board the spaceship, how
long will it take to make the trip? Express your answer in years.
(1 yr is equal to 3.16 × 107 s.)

1. An image of a 10 cm high LED strip is formed using two
converging lenses. The two lenses are separated by a distance of
1.5 m, and the LED strip is 1 m away from the nearest lens. The
focal length of the lens closest to the LED strip is 1 m and that
of the farther lens is 0.2 m.
a) Determine the position of the image formed by this two-lens
assembly, relative to the position of the...

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