Question

Light with a frequency of 3.70 × 1015 Hz strikes a metal surface and ejects electrons that have a maximum kinetic energy of 5.4 eV. What is the work function of the metal?

Answer #1

What is the work function of a metal?

Using a formula, we have

K.E_{max} = h f - _{
}

where, h = planck constant = 6.63 x 10^{-34} J.s

f = frequency of light = 3.70 x 10^{15} Hz

K.E_{max} = maximum kinetic energy = 5.4 eV = 8.6518 x
10^{-19} J

then, we get

(8.6518 x 10^{-19} J) = [(6.63 x 10^{-34} J.s)
(3.70 x 10^{15} Hz)] - _{
}

_{}
= [(2.4531 x 10^{-18} J) - (8.6518 x 10^{-19}
J)]

_{}
= 1.58792 x 10^{-18} J

Converting J into eV :

_{}
= [(1.58792 x 10^{-18} J) (6.241509 x 10^{18}
eV/J)]

_{}
= 9.91 eV

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Question: What is the work function of
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