Question

Protons are to be accelerated in a beam for use in proton therapy. They experience a...

Protons are to be accelerated in a beam for use in proton therapy. They experience a uniform electric
field, E = 50 kN/C , and are accelerated from rest over a distance, d = 1.2m . What is the proton speed
after this acceleration? (5 points)

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In proton-beam therapy, a high-energy beam of protons is fired at a tumor. The protons come...
In proton-beam therapy, a high-energy beam of protons is fired at a tumor. The protons come to rest in the tumor,depositing their kinetic energy and breaking apart the tumor’s DNA, thus killing its cells. The protons gain their energy by being discharged through a type of capacitor with a potential difference of 20MV and have a starting speed of 1.88 x 10^8 m/s. Using what you know of the behavior of a point charge in an electrostatic field and the...
Proton-beam therapy involves firing high-energy protons at a tumor. The protons burrow into the tumor, coming...
Proton-beam therapy involves firing high-energy protons at a tumor. The protons burrow into the tumor, coming to rest. The change in the kinetic energy of the protons goes into the tumor, bursting its DNA, thus killing its cells. In one case, it is desired that 0.10 J of proton energy be deposited in a tumor. To create the proton beam, the protons are accelerated from rest through a 10 MV potential difference. (a) What is the total charge of the...
In proton-beam therapy, a high-energy beam of protons is fired at a tumor. The protons come...
In proton-beam therapy, a high-energy beam of protons is fired at a tumor. The protons come to rest in the tumor, depositing their kinetic energy and breaking apart the tumor
A beam of protons is accelerated easterly from rest through a potential difference of 5.0kV ....
A beam of protons is accelerated easterly from rest through a potential difference of 5.0kV . It enters a region where there exists an upward pointing uniform electric field. This field is created by two parallel plates separated by 15cm with a potential difference of 250 V across them. PART A What is the speed of the protons as they enter the electric field? Express your answer using two significant figures. PART B Find the magnitude of the magnetic field...
2. Proton beam: A beam of protons is fired with a velocity v = 4.0 ×...
2. Proton beam: A beam of protons is fired with a velocity v = 4.0 × 105m/s into a region of uniform magnetic field with B = 230 Gauss, pointing out of the page. a) How far does the beam penetrate into the field region? b) A uniform electric field is also turned on. What magnitude and direction for E will allow the protons to pass through undeflected? c) A square loop with 100 windings 10 cm on each side...
A beam of protons is accelerated through a potential difference of 0.750kV and then enters a...
A beam of protons is accelerated through a potential difference of 0.750kV and then enters a uniform magnetic field traveling perpendicular to the field. a.What magnitude of field is needed to bend these protons in a circular arc of diameter 1.74m ? b.What magnetic field would be needed to produce a path with the same diameter if the particles were electrons having the same speed as the protons?
1--A proton is accelerated from rest by a potential difference of 350v. It then enters a...
1--A proton is accelerated from rest by a potential difference of 350v. It then enters a uniform magnetic field.the orbit radius is 25cm. Find (a) the protons,s speed, (b) the magnetic field strength (c) the period of the motion
A proton is placed in a uniform electric field of 2600N/C . Calculate the magnitude of...
A proton is placed in a uniform electric field of 2600N/C . Calculate the magnitude of the electric force felt by the proton. Calculate the proton's acceleration. Calculate the proton's speed after 1.10 μs in the field, assuming it starts from rest.
A beam of protons (proton mass is 1.67 x 10 -​ 27 kg) moves at 3...
A beam of protons (proton mass is 1.67 x 10 -​ 27 kg) moves at 3 x 10 5​ m/s through a uniform magnetic field with magnitude 2 T. The magnetic field has exactly equal components along the positive ​y and negative ​x axes and no component along the ​z axis. The velocity of each proton lies in the ​xz-​ plane at an angle of 30 0​ ​to the​ z-​ axis. (a) Write the magnetic field ​B and the velocity...
A proton accelerates from rest in a uniform electric field of 580 N/C. At some later...
A proton accelerates from rest in a uniform electric field of 580 N/C. At some later time, its speed is found to be 3.6 ✕ 106 m/s. (a) Calculate the magnitude of the acceleration of the proton (in m/s2). m/s2 (b) How long (in s) does it take the proton to reach the given speed? s 3. [–/1 Points] DETAILS
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT