Question

A 5.20 μF capacitor that is initially uncharged is connected in series with a 5.20 kΩ resistor and an emf source with E= 265 V negligible internal resistance.

1) Just after the circuit is completed, what is the voltage drop across the resistor?

2)Just after the circuit is completed, what is the charge on the capacitor?

3) Just after the circuit is completed, what is the current through the resistor?

Answer 1

1) just after the circuit is completed

the current in the circuit is maximum , all the potential drops across the capacitor

voltage drop across the resistor = E

voltage drop across the resistor = 265 V

the voltage drop across the resistor is 265 V

2)

when the circuit is completed

the capacitor is not charged at all

charge on the capacitor is Zero

3)

current in resistor = E/R

current in resistor = 265/5.2

current in resistor = 51 mA

the current in the resistor is 51 mA or 0.051 A