Question

If an AM radio station is emitting 30000 W in its 1290-kHz radio wave, how many photons is it emitting each second?

n= (answer) x10^31

Answer 1

step:1

Given that

power P=30000 W

frequency f=1290*10^3 Hz

step:2

now we find the number of photons emitted

energy of single photon Ef=hf=6.63*10^-34*1290*10^3=8.6*10^-28 J

the radio station emitted Es=3*10^4 J/s

no.of photons emitted n=Es/Ef=3*10^4/8.6*10^-28

                                    =3.5*10^31