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The coil in the figure carries current i = 1.58 A in the direction indicated, is...

The coil in the figure carries current i = 1.58 A in the direction indicated, is parallel to an xz plane, has 4 turns and an area of 4.75

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Answer #1

m = magnetic moment vector = i*Area * k = 1.58*4.75*10^-3 = 7.5*10^-3 *k

B = magnetic filed = (1.86i - 3.79j - 3.36k) *10^-3 T

a) magnetic potentail energy = - m. B

                                               = - ( 7.5*10^-3 *k ) *   (1.86i - 3.79j - 3.36k) *10^-3

                                               =7.5*10^-3 * 3.36*10^-3

= 25.2 *10^-6


b) Torque = m x B

   = ( 7.5*10^-3 *k ) x (1.86i - 3.79j - 3.36k) *10^-3

                = 7.5*10^-3 ( 1.86 j +3.79 i)

               = (13.95 j + 28.42 i ) *10^-6

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