Question

Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is

|F|=K|QQ′|d2|F|=K|QQ′|d2 ,

where K=14πϵ0K=14πϵ0 , and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1q1q_1 = -12.5 nCnC , is located at x1x1x_1 = -1.730 mm ; the second charge, q2q2q_2 = 31.5 nCnC , is at the origin (xx = 0).

What is (Fnet3)x(Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3q3q_3 = 46.0 nCnC placed between q1q1 and q2q2 at x3x3x_3 = -1.130 mm ?

Your answer may be positive or negative, depending on the direction of the force.

Express your answer numerically in newtons to three significant figures.

Answer 1

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