Question

Infrared observations of a star show that it is most intense at a wavelength of 920...

Infrared observations of a star show that it is most intense at a wavelength of 920 nm (9.20  102 nm). What is the temperature of the star's surface?
_________________________K

If one star has a temperature of 6300 K and another star has a temperature of 7800 K, how much more energy per second will the hotter star radiate from each square meter of its surface?
______________________________times

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Answer #1

Ans

1

Temperature = 3150 K

2

= 2.35 times

Explanation

1

Most intense wavelength

Let T be the temperature of the star's surface. Therefore using Wein's displacement law

T = 3150 K

2

The temperature of first star T1 = 6300 K

The temperature of second star T2 = 7800 K

The ratio of energy per second per unit area from hotter star to cooler star is

Therefore energy per second from the hotter surface will 2.35 times more.

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