Question

Consider the situation from the previous problem, but this time, take air resistance into account.

After we have released the ball and it is travelling upward, the air resistance force will be directed    [ Select ] ["upwards", "downwards] in the [ Select ]   ["same direction as", "opposite direction as"] the velocity.  The acceleration of the ball at that time will be directed [ Select ] ["upwards", "downwards"] with a magnitude that is   [ Select ] ["greater than", "less than", "equal to"] g.  This will cause the ball to slow down [ Select ] ["more quickly", "less quickly", "equally quickly"]    than it would have without air resistance.

After the ball has reached its highest point and begins to fall back down (but before we begin to catch it), the air resistance force will be directed    [ Select ] ["upwards", "downwards"]         in the   [ Select ] ["same direction as", "opposite direction as"] the velocity, and the ball will accelerate  [ Select ] ["upwards", "downwards"] with a magnitude that is [ Select ] ["greater than", "less than", "equal to"] g.  This will cause the ball to speed up [ Select ]    ["more quickly", "less quickly", "equally quickly"] than it would have without air resistance.

Answer 1