Question

Part One: A simple pendulum of length *l* = 0.800 has a
mass = 0.250kg. What is the tension in the string when it is at
angle *theta* = 12.5°? Show your force diagram and work to
support your answer

Part Two: What is the period *T* of the motion of the
pendulum in Part Two? Assume the period is independent of angle
*theta*.

Part Three: What is the period *T* of the motion of the
pendulum in Part One? Assume the period is independent of angle
*theta*.

Part Four: What would be the period *T* of the pendulum
if *l* was unchanged but =0.500kg ?

Part Four: Determine the period *T* of the pendulum if
everything else stays the same, but angle theta = 45°. Do not
assume that the period is independent of angle theta.

Answer #1

Part One : Tension in the string will be given as -

T = m g cos = (0.25 kg) (9.8
m/s^{2}) cos 12.5^{0}

T = (2.45 N) (0.9762)

**T = 2.39 N**

Part Three : The period *T* of the motion of pendulum in
Part One which will be given as -

using a formula, we have

T = 2_{}L /
g

where, L = length of pendulum = 0.8 m

T = 2 (3.14) _{}(0.8
m) / (9.8 m/s^{2})

T = (6.28) (0.2857 sec)

**T = 1.79 sec**

Part Four : If L was unchanged but m = 0.5 kg, then the period
*T* of pendulum which will be given as -

using a formula, we have

T = 2_{}L /
g

where, L = length of pendulum = 0.8 m

T = 2 (3.14) _{}(0.8
m) / (9.8 m/s^{2})

T = (6.28) (0.2857 sec)

**T = 1.79 sec**

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