Question

An electron has an initial speed of 5.65 106 m/s in a uniform 5.23 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.

(a) What is the direction of the electric field?

opposite direction to the electron's initial velocity

same direction as the electron's initial velocity

not enough information to decide

b)How far does the electron travel before coming to rest?

c)How long does it take the electron to come to rest?

d) What is the electron's speed when it returns to its starting point?

Answer 1

Find the acceleration of electron from the given value of electric field and use equation of kinematics where acceleration is opposite to initial velocity and hence it will be taken as negative to find the required solution as shown below