Question

An electron enters a region of space containing a uniform 0.0000149-T magnetic field. Its speed is 121 m/s and it enters perpendicularly to the field. Under these conditions, the electron undergoes circular motion. Find the radius r of the electron\'s path, and the frequency f of the motion.

Answer #1

**=================================
apply centripetal force = magnetic force**

**i.e mv^2/r = qvB,**

**where m = mass o the charged particle**

**v = velocity, r = radius ,**

**q = charge = 1.6*10^-19 C**

**B = magnetic field**

**so now , r = mv/qB**

**so r = 9.11e-31 *
121/(1.6e-19*0.0000149)**

**r = 0.046 mm**

**-----------------------------------**

**T = 1/f = 2piR/V**

**= 2pi (mv)/qBv**

**= 2pim/qB**

**T = 2pim/qB**

**f = qB/2pim**

**f = 1.6e-19 * 0.0000149 /(2*3.14* 9.11e-31)**

**f = 4.16 *10^5 Hz
=================================**

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