A ball thrown horizontally at 25.0 m/s from the roof of the building that is 40.0 m height. How far from the base of the building will the ball be landing?
Given,
The initial velocity of the ball in a horizontal direction,
The initial velocity of the ball in a vertical direction,
The height of the building, h = 40 m
For the vertical motion of the ball, from the equation of the motion,
where t = time taken by the ball to reach the ground
g = acceleration due to gravity =
For the horizontal motion of the ball,
where x = distance traveled by the ball in the x-direction
Hence the ball will land 71.42 meters away from the building.
Get Answers For Free
Most questions answered within 1 hours.