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An electron that is moving through a uniform magnetic field has a velocity v = (42...

An electron that is moving through a uniform magnetic field has a velocity v = (42 km/s)i + 31 km/s)j when it experiences a force F = (-5.000×10-15 N)i + (6.774×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T)

What is By?

What is Bz?

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Answer #1

magnetic force Fb = q*(v cross B)

          i            j            k

          42          31            0

v x B =   0          By              Bz

v x B = i*(31000Bz) + k42000By

Fb = q*(v x B )


-5*10^-15 i + 6.774*10^-15 j = 1.6*10^-19*31000Bz i + 1.6*10^-19*42000By


comparing i


1.6*10^-19*31000Bz = -5*10^-15


Bz = -1 T


comparing j


1.6*10^-19*42000By = 6.774*10^-15


By = -1 T

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