Question

An electron that is moving through a uniform magnetic field has
a velocity v = (42 *km/s*)**i** + 31
*km/s*)**j** when it experiences a force F =
(-5.000×10^{-15} *N*)**i** +
(6.774×10^{-15} *N*)**j** due to the
magnetic field. If Bx = 0, calculate the magnitude of the magnetic
field B. (Tesla = T)

What is By?

What is Bz?

Answer #1

**magnetic force Fb = q*(v cross B)**

**
i
j
k**

**
42
31
0**

**v x B =
0
By
Bz**

**v x B = i*(31000Bz) + k42000By**

**Fb = q*(v x B )**

**-5*10^-15 i + 6.774*10^-15 j = 1.6*10^-19*31000Bz i +
1.6*10^-19*42000By**

**comparing i**

**1.6*10^-19*31000Bz = -5*10^-15**

**Bz = -1 T**

**comparing j**

**1.6*10^-19*42000By = 6.774*10^-15**

**By = -1 T**

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