Question

An electron that is moving through a uniform magnetic field has a velocity v = (42...

An electron that is moving through a uniform magnetic field has a velocity v = (42 km/s)i + 31 km/s)j when it experiences a force F = (-5.000×10-15 N)i + (6.774×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T)

What is By?

What is Bz?

Homework Answers

Answer #1

magnetic force Fb = q*(v cross B)

          i            j            k

          42          31            0

v x B =   0          By              Bz

v x B = i*(31000Bz) + k42000By

Fb = q*(v x B )


-5*10^-15 i + 6.774*10^-15 j = 1.6*10^-19*31000Bz i + 1.6*10^-19*42000By


comparing i


1.6*10^-19*31000Bz = -5*10^-15


Bz = -1 T


comparing j


1.6*10^-19*42000By = 6.774*10^-15


By = -1 T

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An electron that is moving through a uniform magnetic field has a velocity v = (52...
An electron that is moving through a uniform magnetic field has a velocity v = (52 km/s)i + 40 km/s)j when it experiences a force F = (-3.600×10-15 N)i + (4.680×10-15 N)jdue to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T). What is By? What is Bz?
An electron moves through a uniform magnetic field given by = Bx i ̂ +(4.52 Bx)...
An electron moves through a uniform magnetic field given by = Bx i ̂ +(4.52 Bx) j ̂ . At a particular instant, the electron has velocity v → = (2.66 i ̂ +4.30 j ̂ ) m/s and the magnetic force acting on it is (4.31 × 10-19) k ̂ N. Find Bx.
A proton moving in a uniform magnetic field with vec v 1 =1.28*10^ 6 i m/s...
A proton moving in a uniform magnetic field with vec v 1 =1.28*10^ 6 i m/s experiences force vec F 1 =1.38*10^ -16 hat k N N. A second proton with vec v 2 =2.32*10^ 6 hat j m/s experiences vec F 2 =-4.07*10^ -16 hat k N in the same field. what is the magnitude of vector B? whst id yhe direction of vector B?
An electron has velocity V = (29i + 38j) km/s as it enters a uniform magnetic...
An electron has velocity V = (29i + 38j) km/s as it enters a uniform magnetic field B= 50 i µT. What are (a) the radius of the helical path taken by the electron and (b) the pitch of that path? (c) To an observer looking into the magnetic field region from the entrance point of the electron, does the electron spiral clockwise or counterclockwise as it moves? The charge of an electron is -1.602 × 10-19 C and its...
An electron experiences a magnetic force of magnitude 4.60 x 10-15 N when moving at an...
An electron experiences a magnetic force of magnitude 4.60 x 10-15 N when moving at an angle of 60.0° with respect to a magnetic field of magnitude 3.50 ´ 10-3 T. Indicate respective directions of magnetic field vector and the force vector. Find the velocity of the electron (its magnitude and direction).
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You...
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.20 km/s in the +x-direction experiences a force of 2.06×10−16 N in the +y-direction, and an electron moving at 4.40 km/s in the −z-direction experiences a force of 8.40×10−16 N in the +y-direction. Part A: What is the magnitude of the magnetic field? Park B: What is the direction of the magnetic field? (in the xz -plane Part...
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You...
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.30 km/s in the +x-direction experiences a force of 2.10×10−16 N in the +y-direction, and an electron moving at 4.50 km/s in the −z-direction experiences a force of 8.60×10−16 N in the +y-direction. What is the magnitude of the magnetic field? b-What is the direction of the magnetic field? (in the xz-plane)
1. An electron is moving through a magnetic field whose magnitude is 8.99 × 10-4 T....
1. An electron is moving through a magnetic field whose magnitude is 8.99 × 10-4 T. The electron experiences only a magnetic force and has an acceleration of magnitude 3.22 × 1014 m/s2. At a certain instant, it has a speed of 8.44 × 106 m/s. Determine the angle (less than 90o) between the electron's velocity and the magnetic field. 2.Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (Au2+), each with a mass of...
A particle with charge ? 5.50 nC is moving in a uniform magnetic field B? =?(...
A particle with charge ? 5.50 nC is moving in a uniform magnetic field B? =?( 1.24 T )k^. The magnetic force on the particle is measured to be F? =?( 3.40×10?7 N )i^+( 7.60×10?7 N )j^. (A) Are there components of the velocity that are not determined by the measurement of the force? (D)Calculate the scalar product v? ?F? ? (E) What is the angle between v?  and F? ? Give your answer in degrees?
10- A particle moving at speed of 3x105 m/s enters perpendicularly in to a uniform magnetic...
10- A particle moving at speed of 3x105 m/s enters perpendicularly in to a uniform magnetic field of 0.10 tesla .what is the magnitude and the direction of magnetic force acting on the particle by the magnetic field . a) The particle is an electron. b) The particle is a proton.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT