Four 8.00 kg masses are bound into a square by four mass-less rigid rods that are 2.00 m long and form the sides of the square. Find the moment of inertia, I, of this object for rotation about an axis perpendicular to plane of the object through the center of one of the rods.
The answer given in the guide is 96.0kgm^2. How do I get that?
Use the distance of each mass from the given point about which the moment of inertia is to be found. The point will be at the middle or at the center of one of the rods as shown below
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