Question

once we connect two charged plates the charge on them1 will decrease exponentially because the charges...

once we connect two charged plates the charge on them1 will decrease exponentially because the charges flow from one plate to the other due to the potential difference between the two plates. The final answer we arrived today for how much charge Q(t) is left on the plates after closing the switch at t = 0 was Q(t) = Q0e − t/RC , where Q0 is the initial charge on the capacitor plates, R is the resistance of the light bulb, and C is the capacitance of the capacitor.

(a) Show that the the time-constant RC has units of time. Comment on why it must have units of time for the above answer to make sense

(b) Show that if Q(t) decays exponentially, the current flowing through the circuit I(t) will decay exponentially too with the same time-constant RC.

(c) Assuming that the brightness of the lightbulb is proportional to the current through it, show that we can estimate the time-constant from measuring the (exponential) decay of the bulb brightness as a function of time without knowing the constant of proportionality.