Question

A sealed tank holds water to a depth of 2.68 m.Above the water is air, pressurized to 243 kPa. If you open a small hole in the bottom of the tank, exposing the water at the bottom to standard atmospheric pressure, at what speed will the water initially emerge?

v=

Answer 1

Gravitational acceleration = g = 9.81 m/s²

Density of water = = 1000 kg/m³

Atmospheric pressure = P_atm = 101325 Pa

Pressure of the air above the water = P = 243 kPa = 243000 Pa

Depth of the water in the tank = h = 2.68 m

Speed of the water emerging from the hole at the bottom of the tank = V

By Bernoulli's Equation at the top of the water level and at the hole,

V = 18.3 m/s

Speed at which the water will emerge from the hole at bottom initially = 18.3 m/s