Question

A sealed tank holds water to a depth of 2.68 m.Above the water is air, pressurized to 243 kPa. If you open a small hole in the bottom of the tank, exposing the water at the bottom to standard atmospheric pressure, at what speed will the water initially emerge?

v=

Answer #1

Gravitational acceleration = g = 9.81 m/s^{2}

Density of water =
= 1000 kg/m^{3}

Atmospheric pressure = P_{atm} = 101325 Pa

Pressure of the air above the water = P = 243 kPa = 243000 Pa

Depth of the water in the tank = h = 2.68 m

Speed of the water emerging from the hole at the bottom of the tank = V

By Bernoulli's Equation at the top of the water level and at the hole,

V = 18.3 m/s

**Speed at which the water will emerge from the hole at
bottom initially = 18.3 m/s**

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