A generator has 50 turns of wire, each with area 0.01m^2 , that rotate within a 0.60-T magnetic field. What is the peak EMF generated when the armature turns at (a) 1000 rpm (b) 2500 rpm
Given the number of turns n= 50, Area of loop winding A= 0.01 m2, Magnetic field b=0.60 T
Emf formula for the generator is given by, if
= 900
than emf will maximum, is the angle between area and magnetic
field.
Case1 N=1000 rpm , =
= 104.71
rad/s,
=
(50)(0.01)(0.60)(104.71) =31.413 N-m
Case2 N=2500 rpm,
= 261.8 rad/s,
=
(50)(0.01)(0.60)(261.8) = 78.54 N-m
So ad RPM increses Peak emf also increases.
Get Answers For Free
Most questions answered within 1 hours.