Question

A generator has 50 turns of wire, each with area 0.01m^2 , that
rotate within a 0.60-T magnetic field. **What is the peak EMF
generated when the armature turns at (a) 1000 rpm (b) 2500
rpm**

Answer #1

Given the number of turns n= 50, Area of loop winding A= 0.01
m^{2}, Magnetic field b=0.60 T

Emf formula for the generator is given by, if
= 90^{0}
than emf will maximum, is the angle between area and magnetic
field.

Case1 N=1000 rpm , = = 104.71 rad/s, = (50)(0.01)(0.60)(104.71) =31.413 N-m

Case2 N=2500 rpm, = 261.8 rad/s, = (50)(0.01)(0.60)(261.8) = 78.54 N-m

So ad RPM increses Peak emf also increases.

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