here,
1)
the mass of sliding crate , m1 = 15.3 kg
theta = 36.9 degree
s = 1.4 m
the work done by gravity on the sliding crate , Wg = - change in gravitational potential energy
Wg = - (m1 * g * s * sin(theta))
Wg = - 15.3 * 9.81 * 1.4 * sin(36.9)
Wg = - 126.1 J
2)
the mass of sliding crate , m1 = 12.4 kg
theta = 36.9 degree
s = 1.7 m
the tension in the rope , T = 121.5 N
frictional force , ff = 21.5 N
the total Work done on sliding crate , W = Wff + Wg + Wt
W = (- ff * s ) + ( - m1 * g * s * sin(theta) + (T * s))
W = 1.7 * ( - 21.5 - 12.4 * 9.81 * sin(36.9) + 121.5) J
W = 45.9 J
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