At time t, the vector ~r = 4t2i − (2t + 6t 2)ˆj gives the position of a 3 kg particle relative to the origin of an xy coordinate system (~r is in meters and t is in seconds). What is the torque (in Newton-meters) acting on the particle relative to the origin?
ANSWER IS 48t, PLEASE EXPLAIN IN DETAIL HOW YOU GOT IT
Therefore the torque acting on particle relative to origin is 48t Nm.
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