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At time t, the vector ~r = 4t2i − (2t + 6t 2)ˆj gives the position...

At time t, the vector ~r = 4t2i − (2t + 6t 2)ˆj gives the position of a 3 kg particle relative to the origin of an xy coordinate system (~r is in meters and t is in seconds). What is the torque (in Newton-meters) acting on the particle relative to the origin?

ANSWER IS 48t, PLEASE EXPLAIN IN DETAIL HOW YOU GOT IT

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Answer #1

Therefore the torque acting on particle relative to origin is 48t Nm.

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