Question

At time t, the vector ~r = 4t^{2}i − (2t + 6t
^{2})ˆj gives the position of a 3 kg particle relative to
the origin of an xy coordinate system (~r is in meters and t is in
seconds). What is the torque (in Newton-meters) acting on the
particle relative to the origin?

ANSWER IS 48t, PLEASE EXPLAIN IN DETAIL HOW YOU GOT IT

Answer #1

Therefore the torque acting on
particle relative to origin is **48t** Nm.

If you have doubt in any part of the solution, feel free to ask.

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