Question

You leave on a mission to a distant star. Your craft accelerates at a 0.65 g for 30 days. From your point of view, you spend the next 1000 days moving at this speed. rom the point of view of an earth observer, how long is this period of steady travel? Express your answer in days to five significant figures.

Answer 1

Answer: ~ 1.51797 days

<<<<<<<< explanation >>>>>>>>>>>>

Given:

a=0.65g=0.65*9.8 =6.37 m/s²

t=30 days=30*24*60*60=2592000 seconds

using equation of motion

V=U+at (assuming intial speed =0)

V=at= 6.37*2592000 = 16511040 m/s

at this speed we travel 1000 days

T2 = 1000/= = 1001.517974063 days

so time difference = 1001.517974063 - 1000 = 1.51797 days

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