Question

The Arrhenius type equation (I = exp (-E / kT), is solved by graphing the natural logarithm of the intensity TL (In (I), with respect to the inverse of the temperature in degrees Kelvin multiplied with the Boltzmann constant (1 / Tk ).
The value of the intersection on the y axis will correspond to In (I), and the slope of the line will be equal to –E / k. The activation energy calculation is finally:
E = -m * k * Tm
where: E is the activation energy (eV), m is the slope, k is the Boltzmann constant (8.6x10-5 eV / K), and Tm is the temperature of the maximum of the brightness curve in Kelvin (K) .

How can I determine the activation energy point by point on a graph where there are temperature values on the x axis and intensity on the y axis? Could you explain to me the value that the slope plays and how it could be derived for each point?

Could you give me an idea on how to calculate the activation energy?

Answer 1