Question

The drawing shows a triple jump on a checkerboard, starting at the center of square A...

The drawing shows a triple jump on a checkerboard, starting at the center of square A and ending on the center of square B. Each side of a square measures 5.3 cm. What is the magnitude of the displacement of the colored checker during the triple jump (there is only one right corner)?

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Answer #1

Side of the square = 5.3 cm

So, diagonal length of the square, d = (5.3)2+(5.3)2 cm = 7.495 cm

Jump 1 is from center of 1st square to the center of 5th square = 4d = 4 x 7.495 cm = 29.98 cm

Jump 2 is from center of 1st square to the center of 3rd square = 2d = 2 x 7.495 cm = 14.99 cm

The two jumps forms a 90o angle,

Applying pythagoras theorem, Displacement = [(29.98)2+(14.99)2] cm = 33.52 cm

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