Question

when you sank a piece of metal of a mass m= 64.5 g and a density of 3.78 g/cm cubed into the watwr, it went to the bottom of the water container and was fully covered by water. how big was the buoyant force received by the metal block after it was fully submerged into water

Answer 1

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SOLUTION:

Given that,

Mass of the metal, m = 64.5 g

Density of the metal, D = 3.78 g/cm³

Therefore, Total volume of the metal is given by:

According to Archimedes principle, Buoyant force on the metal will be equal to the weight of the fluid displaced by the object.

We have, Density of water, d = 0.001 kg/cm³

Therefore, Mass of fluid displaced, m = V x d = 17.06 cm³ x 0.001 kg/cm³ = 0.01706 kg

Therefore, Buoyant force is given by:

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