Question

On Earth, a wooden block of mass m_b= 0.5 kg hangs from the ceiling by a very long, massless string. A chunk of putty of mass m_p= 0.25 kg, starting at a distance of 10 m away from the block is thrown vertically upward at an initial speed of +35 m/s toward the block, striking the block and sticking to it. How high does the putty-block system rise above the original position of the wooden block?

Answer 1

its collision question of inelastic basically garvity is added in it because u know in inelastic collison both stick toghther after collision

so speed of block after before just collision

by coservTION OF ENERGY

initial K.E = final K.E+P.E

0.5mv²=0.5mv_f²+mgh

v_f =32.078029 m/s before strike block

now agagin coservation of momentum

before strike=after strike

Mp*Vf=(Mp+Mb)*Vs

Vs is after strike or velocity of stick both block and chunk of putty

0.25*32.0780=(0.25+0.5)Vs

Vs=10.6926m/s

so height they gain together

bycoservation of energy

mgh=0.5mVs²

h=5.8333m