Question

Can someone explain the following: ∆U= Q∆V but Ucapacitor= 1/2QV? In other words, why is the...

Can someone explain the following:

∆U= Q∆V but Ucapacitor= 1/2QV?

In other words, why is the potential energy of capacitor multiplied by 1/2 but the change in PE is not?

Homework Answers

Answer #1

The potential energy of the capacitor is given by,

In the above equation the capacitance C of a capacitor is constant, and when potential energy changes the potential will change. (In the first equation both charge and voltage are both variables, and they both can change for change in potential energy).

Taking derivative of the potential energy with respect to voltage we can write,

The differentials can be approximated by small change, hence we can write,

We know that Q = CV. Hence we can write,

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