Question

Suppose that 2.8 moles of a monatomic ideal gas (atomic mass = 4.7

Answer 1

1)

dQ = dU = n*Cv*dT = 2.8*12.47*(500-300) = 6983.2 J

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2)

here as the volume is constant the work done is zero

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3)
fromideal gas equation

P2*V = n*R*T2

P2 = n*R*T2/V

P2 = (2.8*8.314*500)/0.28 = 41570 Pa

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d)

n = m/M

M = m/n = n*N*u/m = N*u = 6.022e23*1.63e-26 = 0.00981586

Vavg = sqrt(3RT2/M)

Vavg = sqrt(3*8.314*500)/(0.00981586) = 1127.2 m/s

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5)
dQ = n*Cp*dT = 2.8*20.79*(500-300) = 11642.4 J

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6)

W = dQ - dU = 11642.4 - 6983 = 4659.4 J